7p^2-38p+p^2=0

Solution for 7p^2-38p+p^2=0 equation:

7p^2-38p+p^2=0

We add all the numbers together, and all the variables

8p^2-38p=0

a = 8; b = -38; c = 0;
Δ = b2-4ac
Δ = -382-4·8·0
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-38)-38}{2*8}=\frac{0}{16}
=0
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-38)+38}{2*8}=\frac{76}{16}
=4+3/4
$